Work and Energy

Work and Energy MDCAT MCQs with answers

97 past paper MCQs from Physics unit 3, Work and Energy, across 6 topics. They are arranged topic by topic; bigger topics show a sample here and link to their full set and to study notes. Tap “Show answer” for the correct option and a short solution.

Work

1.A 10 N force moves a body around a circular path of radius 50 cm. What is the work done in completing one revolution? (MDCAT 2020)

  1. 25 J
  2. zero
  3. 31.42 J
  4. 500 J
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Correct answer: (b) zero

The body returns to its starting point, so the displacement is zero and so is the work.

2.The area under a force-displacement graph gives us the: (MDCAT 2020)

  1. displacement
  2. power
  3. work
  4. acceleration
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Correct answer: (c) work

Force multiplied by displacement is work, and that product is the area under the graph.

3.The work done by a variable force can be found by dividing the: (MDCAT 2023)

  1. force into small intervals
  2. displacement into small intervals
  3. both force and displacement into small intervals
  4. displacement into intervals at different angles
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Correct answer: (b) displacement into small intervals

Over a small enough displacement the force is effectively constant, so $W=\sum F\Delta d$ is the area under the force-displacement graph.

All 24 Work MCQs → Work notes →

Energy and Kinetic Energy

4.A particle of mass $m$ at rest is acted upon by a force $P$ for a time $t$. Its kinetic energy after time $t$ is: (MDCAT 2022)

  1. $P^2t^2/m$
  2. $P^2t^2/2m$
  3. $P^2t^2/3m$
  4. $P^2t^2/4m$
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Correct answer: (b) $P^2t^2/2m$

The impulse gives $p=Pt$, and $E_k=p^2/2m=P^2t^2/2m$.

5.An 8.0 kg box slides along a horizontal frictionless floor at $3\ \mathrm{m\,s^{-1}}$ and meets a light spring that compresses 12 cm before the box stops. Calculate the retarding force of the spring. (MDCAT 2023)

  1. 3 N
  2. 30 N
  3. 300 N
  4. 3000 N
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Correct answer: (c) 300 N

$\tfrac{1}{2}mv^2=\tfrac{1}{2}(8)(3)^2=36$ J, and $F=W/d=36/0.12=300$ N.

6.Two bodies with kinetic energies in the ratio 4 : 1 are moving with equal linear momentum. The ratio of their masses is: (MDCAT 2023)

  1. 1 : 4
  2. 4 : 1
  3. 1 : 2
  4. 2 : 1
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Correct answer: (a) 1 : 4

With $p$ equal, $E_k=p^2/2m$, so the kinetic energy is inversely proportional to the mass.

All 20 Energy and Kinetic Energy MCQs → Energy and Kinetic Energy notes →

Potential Energy and Absolute Potential Energy

7.A 3 kg stone falls from a 20 m high platform. Find its speed at a height of 10 m. (MDCAT 2020)

  1. $190\ \mathrm{m\,s^{-1}}$
  2. $14\ \mathrm{m\,s^{-1}}$
  3. $10\ \mathrm{m\,s^{-1}}$
  4. $100\ \mathrm{m\,s^{-1}}$
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Correct answer: (b) $14\ \mathrm{m\,s^{-1}}$

It has fallen 10 m, so $v=\sqrt{2gh}=\sqrt{2(10)(10)}\approx14\ \mathrm{m\,s^{-1}}$.

8.A long spring, when stretched by a distance $x$, has potential energy $V$. On increasing the stretching to $nx$, the potential energy of the spring will be: (MDCAT 2022)

  1. $nV$
  2. $V/n$
  3. $n^2V$
  4. $V/n^2$
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Correct answer: (c) $n^2V$

$E=\tfrac{1}{2}kx^2$ goes as the square of the extension.

9.Ignoring friction and the extra forces exerted by the muscles, a pole vault is the conversion of an athlete's running kinetic energy into gravitational potential energy. If an athlete is to lift his body 5 m during a vault, what speed must he have when he plants his pole? (MDCAT 2022)

  1. $5\ \mathrm{m\,s^{-1}}$
  2. $10\ \mathrm{m\,s^{-1}}$
  3. $15\ \mathrm{m\,s^{-1}}$
  4. $20\ \mathrm{m\,s^{-1}}$
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Correct answer: (b) $10\ \mathrm{m\,s^{-1}}$

$\tfrac{1}{2}mv^2=mgh$ gives $v=\sqrt{2gh}=\sqrt{2(10)(5)}=10\ \mathrm{m\,s^{-1}}$.

All 19 Potential Energy and Absolute Potential Energy MCQs → Potential Energy and Absolute Potential Energy notes →

Power

10.The kilowatt-hour is a unit of: (MDCAT 2020)

  1. electric energy
  2. power
  3. momentum
  4. intensity
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Correct answer: (a) electric energy

It is a power multiplied by a time, so it measures energy.

11.One kilowatt-hour is equal to: (MDCAT 2020)

  1. $1.6\times10^{6}\ \mathrm{J}$
  2. $3.6\times10^{6}\ \mathrm{J}$
  3. $9.1\times10^{6}\ \mathrm{J}$
  4. $1.6\times10^{-19}\ \mathrm{J}$
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Correct answer: (b) $3.6\times10^{6}\ \mathrm{J}$

$1000\ \mathrm{W}\times3600\ \mathrm{s}=3.6\times10^{6}$ J.

12.The consumption of energy by a 60 W bulb in 2 s is: (MDCAT 2022)

  1. 120 J
  2. 60 J
  3. 30 J
  4. 0.02 J
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Correct answer: (a) 120 J

$E=Pt=60\times2=120$ J.

All 30 Power MCQs → Power notes →

Work Done Against Friction in a Resistive Medium

13.Which of the following is a non-conservative force? (MDCAT 2024)

  1. frictional force
  2. electric force
  3. elastic spring force
  4. gravitational force
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Correct answer: (a) frictional force

The work done against friction depends on the path taken and is not recovered, so friction is non-conservative.

14.In inter-conversion of energy, the work done against the friction is: (SZABMU MDCAT 2023)

  1. f + h
  2. f - h
  3. fh
  4. f / h
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Correct answer: (c) fh

Work is force times distance, so the work against a friction $f$ over a distance $h$ is $fh$.

15.A bullet of mass 10 g leaves a rifle at an initial velocity of 1000 m/s and strikes earth at the same level with a velocity of 500 m/s. The work done in overcoming the resistance of air will be: (PMC Practice 2021)

  1. 500 J
  2. 5000 J
  3. 3750 J
  4. 475 J
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Correct answer: (c) 3750 J

$\tfrac12\times0.01\times(1000^2-500^2)$ is $3750\,\mathrm{J}$ lost to the air.

Work Done Against Friction in a Resistive Medium notes →

Energy Losses and Efficiency

16.An engine pumps 400 kg of water through a height of 10 m in 40 s. Find the power of the engine if its efficiency is 80%? Take g = 10msJ\-2. (PMC MDCAT 2022)

  1. 1.25 W
  2. 125 W
  3. 1.25 kW
  4. 12.5 kW
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Correct answer: (c) 1.25 kW

The useful power is $400\times10\times10/40=1000\,\mathrm{W}$, and at $80\%$ efficiency the engine must supply $1.25\,\mathrm{kW}$.

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