Elastic and Inelastic Collisions

Elastic and Inelastic Collisions: MDCAT Physics notes

Elastic and Inelastic Collisions notes for MDCAT: conservation of momentum and KE, relative speeds, equal-mass exchange, sticking bodies and traps.

Unit: Force and Motion · Updated

Types of collision

In every collision of an isolated system, momentum is conserved and total energy is conserved. What distinguishes the types is the kinetic energy.

FeatureElasticInelastic
MomentumConservedConserved
Kinetic energyConservedNot conserved (some becomes heat, sound, deformation)
Total energyConservedConserved
ExamplesCollisions of gas molecules, ideal billiard ballsCar crashing into a tree, bullet embedding in a block

A perfectly (completely) inelastic collision is one in which the bodies stick together and move with a common velocity; maximum KE is lost.

Elastic collision in one dimension

Conserving both momentum and KE for a head-on collision gives the important result:

$$u_1 - u_2 = -(v_1 - v_2)$$

The relative speed of approach equals the relative speed of separation, regardless of the masses. If 2 kg at $5\ \text{m s}^{-1}$ catches 3 kg at $1\ \text{m s}^{-1}$, they approach at $4\ \text{m s}^{-1}$ and separate at $4\ \text{m s}^{-1}$.

Final velocities (for $m_2$ initially at rest):

$$v_1 = \frac{m_1 - m_2}{m_1 + m_2}u_1, \qquad v_2 = \frac{2m_1}{m_1+m_2}u_1$$

Special cases

  • Equal masses: the bodies exchange velocities ($v_1 = u_2$, $v_2 = u_1$). A moving ball hitting an identical ball at rest stops, and the second moves off with the first one's speed.
  • Light body hits a very heavy body at rest: it rebounds with nearly the same speed; the heavy body barely moves.
  • Heavy body hits a light body at rest: heavy body continues almost unchanged; light body moves off at nearly $2u_1$.

Bodies that stick together

$$v = \frac{m_1u_1 + m_2u_2}{m_1 + m_2}$$

  • 2 kg at $3\ \text{m s}^{-1}$ sticks to 1 kg at rest: $v = 6/3 = 2\ \text{m s}^{-1}$.
  • Mass dropped vertically into a moving wagon: it brings no horizontal momentum, so $1000 \times 50 = 1250\,v$, $v = 40\ \text{km h}^{-1}$.
  • Momentum is a vector: if two equal momenta at right angles combine, the composite moves at $45^\circ$ to each.

Zero total momentum

Two equal masses approaching each other with equal speeds have total momentum $mv + (-mv) = 0$ before collision, and so zero after as well, whatever the type of collision.

Key formulas

  • $m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$
  • Elastic: $\tfrac12 m_1u_1^2 + \tfrac12 m_2u_2^2 = \tfrac12 m_1v_1^2 + \tfrac12 m_2v_2^2$
  • Elastic: $u_1 - u_2 = v_2 - v_1$
  • Sticking: $v = (m_1u_1+m_2u_2)/(m_1+m_2)$

Common MDCAT traps

  • Momentum is conserved in all collisions; only KE separates elastic from inelastic.
  • In a crash (inelastic), KE is not conserved but momentum is.
  • Relative speed of separation equals approach in elastic collisions; it does not depend on masses.
  • Total energy is conserved even in inelastic collisions; only KE is lost.

Quick revision

  • Elastic: momentum + KE conserved.
  • Perfectly inelastic: bodies stick together.
  • Equal masses, elastic, head-on: velocities exchange.
  • Equal and opposite momenta: total zero before and after.

Test yourself

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