Electric Potential Due to a Point Charge

Electric Potential Due to a Point Charge: MDCAT Physics notes

Electric Potential Due to a Point Charge for MDCAT: V = kq/r, scalar addition of potentials, V and E at midpoints, and V versus E ratio problems.

Unit: Electrostatics · Updated

The formula

The potential at a distance $r$ from a point charge $q$ is the work done per unit positive charge in bringing it from infinity to that point:

$$V = \frac{1}{4\pi\varepsilon_0}\frac{q}{r} = \frac{kq}{r}$$

  • $V$ is positive near a positive charge and negative near a negative charge.
  • $V \propto 1/r$: doubling the distance halves the potential.
  • $V = 0$ at infinity. Potential measured from this zero is called absolute potential.

Example: potential 1 m from a $+3\ \mu$C charge is $V = 9\times10^9\times3\times10^{-6}/1 = 2.7\times10^4$ V.

Comparing $V$ and $E$ for a point charge

QuantityFormulaDepends on $r$ asNature
Field$kq/r^2$$1/r^2$Vector
Potential$kq/r$$1/r$Scalar

Also $E = V/r$ for a point charge. To link the two in ratio questions, first find how $r$ changes from the given quantity, then apply it to the other.

Example: at a point the field is $E$ and potential $V$. Where the field is $E/9$, the distance is $3r$, so the potential is $V/3$.

Several charges: add as scalars

Because potential is a scalar, the total potential at a point is the algebraic sum of the potentials of all charges, taking signs into account. Fields, being vectors, must be added with direction.

Midpoint between two charges

ChargesPotential at midpointField at midpoint
$+q$ and $+q$ (equal like)$2kq/d \neq 0$ (adds)Zero (equal and opposite)
$+q$ and $-q$ (equal unlike)Zero (cancels)Not zero (adds, points to $-q$)

Here $d$ is the distance from each charge to the midpoint. These two results are opposite of each other and are frequently tested together.

Worked example

Charges $+2\ \mu$C and $-6\ \mu$C are 4 m apart. Potential at the midpoint (2 m from each):

$$V = \frac{9\times10^9(2\times10^{-6})}{2} + \frac{9\times10^9(-6\times10^{-6})}{2} = 9000 - 27000 = -18000\ \text{V}$$

Equipotentials

Around a point charge, surfaces of constant potential are spheres centred on the charge. No work is done moving a charge along an equipotential, and field lines cross equipotentials at right angles.

Key formulas

  • $V = kq/r$
  • $E = kq/r^2 = V/r$
  • $V_{\text{total}} = \sum kq_i/r_i$ (with signs)

Common MDCAT traps

  • Using $1/r^2$ for potential. Potential falls as $1/r$.
  • Midpoint of equal like charges: $E = 0$ but $V \neq 0$.
  • Midpoint of equal unlike charges: $V = 0$ but $E \neq 0$.
  • Forgetting the micro prefix: $1\ \mu$C $= 10^{-6}$ C.

Quick revision

  • Potential is a scalar; add potentials with signs.
  • Doubling $r$ halves $V$ and quarters $E$.
  • Absolute potential is referred to zero at infinity.
  • Equipotentials around a point charge are concentric spheres.

Test yourself

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