Laws of Thermodynamics

Laws of Thermodynamics: MDCAT Chemistry notes

Laws of Thermodynamics MDCAT notes: first law, sign conventions, pressure-volume work, constant volume and pressure, bomb calorimeter.

Unit: Thermochemistry and Energetics of Chemical Reactions · Updated

First law of thermodynamics

Energy can neither be created nor destroyed, but can be converted from one form to another. The total energy of a system and its surroundings remains constant.

Mathematically:

$$\Delta E = q + w$$

  • $\Delta E$: change in internal energy of the system.
  • $q$: heat absorbed by the system (positive) or released (negative).
  • $w$: work done on the system (positive) or by the system (negative).

Pressure-volume work

When a gas expands or contracts against a constant external pressure:

$$w = -P\Delta V = -P(V_2 - V_1)$$

  • Expansion ($\Delta V \gt 0$): the system does work, so $w$ is negative.
  • Compression ($\Delta V \lt 0$): work is done on the system, so $w$ is positive.
  • If a reaction changes the number of moles of gas, the volume of the system changes and work is done.
  • $1\ \mathrm{dm^3\,atm} = 101.3\ \mathrm{J}$.

Worked example

A gas expands from $10\ \mathrm{dm^3}$ to $16\ \mathrm{dm^3}$ against a constant 3 atm. $w = -3\times6 = -18\ \mathrm{dm^3\,atm} = -18\times101.3 \approx -1823\ \mathrm{J}$. The negative sign shows the gas did work on the surroundings.

Gas-evolving reactions

When a reaction gives off a gas, for example a carbonate or a metal reacting with dilute acid, the gas pushes back the atmosphere. The system does work on the surroundings, so $w$ is negative. The sign of $q$ depends on whether that particular reaction releases or absorbs heat.

Applications of the first law

ConditionResultMeaning
Constant volume ($\Delta V = 0$)$w = 0$, so $\Delta E = q_v$Heat supplied equals the change in internal energy
Constant pressure$q_p = \Delta E + P\Delta V = \Delta H$Heat supplied equals the enthalpy change
Isolated system$q = 0$, $w = 0$, so $\Delta E = 0$Energy is conserved

A bomb calorimeter is a sealed, rigid steel vessel. Its volume is constant, so it measures $\Delta E$. A coffee-cup (glass) calorimeter works at constant pressure and measures $\Delta H$.

Hess's law is an application of the first law: since energy is conserved and $H$ is a state function, the enthalpy change is the same by any route.

Second law (brief)

The first law tells us energy is conserved but not which direction a change will go. The second law states that in a spontaneous process the total entropy (disorder) of the system and surroundings increases. Heat flows naturally from a hot body to a cold one, never the reverse on its own.

Key formulas

  • $\Delta E = q + w$
  • $w = -P\Delta V$
  • $\Delta E = q_v$ and $\Delta H = q_p = \Delta E + P\Delta V$

Common MDCAT traps

  • The correct form of the first law is $\Delta E = q + w$, not $\Delta E = w - q$ or $\Delta H = q + w$.
  • In expansion work is done by the gas, so $w$ is negative.
  • At constant volume the heat equals $\Delta E$, not $\Delta H$.
  • A bomb calorimeter keeps volume constant, not pressure.
  • Keep units consistent: $\mathrm{dm^3\,atm}$ must be converted to J before adding to $q$.

Quick revision

  • First law: energy is conserved.
  • $\Delta E = q + w$.
  • Expansion work is negative.
  • Bomb calorimeter works at constant volume.
  • Hess's law follows from the first law.

Test yourself

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