1.The Born-Haber cycle is used to determine the lattice energy of ionic compounds. It is an application of: (MDCAT 2022)
- Henry's law
- Le Chatelier's principle
- Hess's law
- the common ion effect
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Correct answer: (c) Hess's law
The cycle adds the enthalpies of a set of steps to reach the same final state, which is Hess's law.
2.The heat of formation of CO and CO2 are -26.4 Kcal and -94.0 Kcal respectively. The heat of combustion of carbon monoxide according to Hess's Law will be: (SIBA MDCAT 2025)
- +26.4Kcal
- -67.6Kcal
- +94.0Kcal
- -120.4Kcal
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Correct answer: (b) -67.6Kcal
Burning carbon monoxide is the formation of carbon dioxide less the formation of the monoxide, $-94.0-(-26.4)$, or $-67.6\,\mathrm{kcal}$.
3.ΔH can be measured indirectly by applying (KMU MDCAT 2024)
- Avogadro's law
- Faraday's law
- Gas's law
- Hess's law
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Correct answer: (d) Hess's law
Hess’s law lets an enthalpy change be got from any convenient route between the same two states.
4.DeltaH° for sublimation of one mole of iodine: H2(g) + I2(g) → 2HI(g) DH = 51.8kJ/mol H2(g) + I2(s) → 2HI(g) DH = -10.5kJ/mol (NUMS MDCAT 2024)
- 41.3 kJ/mol
- 62.3 kJ/mol
- 53.5 kJ/mol
- 36.5 kJ/mol
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Correct answer: (b) 62.3 kJ/mol
Subtracting the second equation from the first leaves the sublimation, $51.8-(-10.5)$, that is $62.3\,\mathrm{kJ\,mol^{-1}}$.
5.Q.88 Born-Haber cycle is used to determine the Lattice energy of ionic compounds. It is the application of (UHS MDCAT 2023)
- Henry's law
- Le - Chatleir's Principle
- Hess's law
- Common ion effect
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Correct answer: (c) Hess's law
The cycle adds enthalpies round a closed path, which is Hess’s law.
6.Which of the following law Is an application of first law of thermodynamics? (PMC MDCAT 2022)
- Hess's law
- Dalton's law
- Moseley's Law
- Avogadro's law
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Correct answer: (a) Hess's law
Hess’s law follows from the conservation of energy applied to enthalpy.
7.Standard enthalpy of combustion of graphite at 25 oC is –393.51 kJ mol-1 and that of diamond is –395.41 kJ mol-1. The enthalpy change for graphite is: (UHS MDCAT 2015)
- – 1.91
- +2.1
- –2.1
- +1.91
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Correct answer: (d) +1.91
Subtracting the two combustion enthalpies leaves $+1.91\,\mathrm{kJ\,mol^{-1}}$ for graphite turning to diamond.