Thermochemistry and Energetics of Chemical Reactions
Thermochemistry and Energetics of Chemical Reactions MDCAT MCQs with answers
50 past paper MCQs from Chemistry unit 8,
Thermochemistry and Energetics of Chemical Reactions, across 7 topics. They are arranged topic by topic; bigger topics show a
sample here and link to their full set and to study notes. Tap “Show answer” for the correct option and a short solution.
8.The Born-Haber cycle is used to determine the lattice energy of ionic compounds. It is an application of: (MDCAT 2022)
Henry's law
Le Chatelier's principle
Hess's law
the common ion effect
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Correct answer: (c) Hess's law
The cycle adds the enthalpies of a set of steps to reach the same final state, which is Hess's law.
9.The heat of formation of CO and CO2 are -26.4 Kcal and -94.0 Kcal respectively. The heat of combustion of carbon monoxide according to Hess's Law will be: (SIBA MDCAT 2025)
+26.4Kcal
-67.6Kcal
+94.0Kcal
-120.4Kcal
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Correct answer: (b) -67.6Kcal
Burning carbon monoxide is the formation of carbon dioxide less the formation of the monoxide, $-94.0-(-26.4)$, or $-67.6\,\mathrm{kcal}$.
10.ΔH can be measured indirectly by applying (KMU MDCAT 2024)
Avogadro's law
Faraday's law
Gas's law
Hess's law
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Correct answer: (d) Hess's law
Hess’s law lets an enthalpy change be got from any convenient route between the same two states.
11.The enthalpy change when one mole of water is formed by the reaction of an acid with an alkali under standard conditions is known as the: (MDCAT 2024)
enthalpy of formation
enthalpy of reaction
enthalpy of combustion
enthalpy of neutralization
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Correct answer: (d) enthalpy of neutralization
Acid plus alkali making one mole of water is the enthalpy of neutralization.
12.For endothermic reaction, enthalpy change is: (SZABMU MDCAT 2025)
ΔHreactant>ΔHproduct
ΔHreactant<ΔHproduct
ΔHreactant=ΔHproduct
ΔHreactant=ΔHproduct=0
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Correct answer: (b) ΔHreactant<ΔHproduct
An endothermic reaction takes heat in, so the products hold more enthalpy than the reactants.
13.The enthalpy change when1 Mole of water is formed by the reaction of acid with an alkali under standard conditions is known as: (UHS MDCAT 2024)
14.If 100 KJ of heat is absorbed by the system and 40 KJ of work is done on the system what is the change of Internal energy? (UHS MDCAT 2025)
-60 KJ
+60 KJ
-140 KJ
+140 KJ
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Correct answer: (d) +140 KJ
Heat absorbed and work done on the system both add, so the internal energy rises by $140\,\mathrm{kJ}$.
15.An increase in the internal energy of a chemical system can lead to all EXCEPT: (KMU MDCAT 2025)
An increase in temperature due to rise in kinetic energy of molecules
A phase change such as melting or evaporation
A chemical reaction if energy supplied is sufficient to break bonds
An increase in temperature due to drop in kinetic energy of molecules
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Correct answer: (d) An increase in temperature due to drop in kinetic energy of molecules
Internal energy rises with the kinetic energy of the molecules, so a drop in that energy cannot raise the temperature.
16.When 1 mole of ice melts at 0°C and constant pressure of 1 atmosphere, 6025 J of heat is absorbed by the system. The molar volume of ice and water are 0.020 and 0.018 dm³, respectively. Calculate ΔE. (1dm³.atm=101.33J) (KMU MDCAT 2024)
6010.20J
6015.20J
6020.20J
6025.20J
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Correct answer: (d) 6025.20J
The volume falls slightly on melting, so the surroundings do a little work and $\Delta E$ is a shade above the heat absorbed.
17.Calculate the work done when 1 mole of an ideal gas expands from 15 dm³ to 20 dm³ against a constant external pressure of 2 atmospheres. (KMU MDCAT 2024)
-10 atm.dm³
-5 atm.dm³
5 atm.dm³
10 atm.dm³
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Correct answer: (a) -10 atm.dm³
$w=-P\Delta V=-2\times5$, which is $-10\,\mathrm{atm\,dm^3}$; the sign says the gas did the work.
18.Expansion takes place when gas evolves during reaction between carbohydrates and dilute HCl. Predict energy change and work done: (NUMS MDCAT 2024)
w is positive, q is negative
w is negative, q is positive
q is positive, no work done
w is positive, q is positive
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Correct answer: (b) w is negative, q is positive
The gas pushes back the surroundings, so the system does work and the sign of $w$ is negative while heat is absorbed.
19.The correct equation for the first law of thermodynamics is: (SZABMU MDCAT 2023)
∆E = q + w
∆E = w - q
∆E = ∆q - p∆v
∆E = ∆q + p∆v
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Correct answer: (a) ∆E = q + w
The first law is $\Delta E=q+w$: heat put in and work done on the system.